A square, 0.762 m on a side, is mounted so that it can rotate about an axis that

Question

A square, 0.762 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. The axis is perpendicular to the plane of the square. A force of 21.8 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque that such a force could produce? The steering wheel of a car has a radius of 0.18 m, and the steering wheel of a truck has a radius of 0.28 m. The same force is applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car?

Explanation / Answer

Torque = Force × perpendicular distance from the axis of rotation to the line of action of force

For maximum torque the perpendicular distance should be maximum and it can only be maximum when force is applied at the corner of square and perpendicular to the line joining the center to that corner.

So maximum Torque = F×(a/2)

Maximum torque = 21.8×0.762/2

= 11.746 N-m

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