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shared with me Google Drive x E Case Study 5 Group Discussio x Physics 2206-2017

ID: 1561920 • Letter: S

Question

shared with me Google Drive x E Case Study 5 Group Discussio x Physics 2206-2017 spring H x Manuel C www.webassign net 15258640 t/web/Student/Assignment-Responses/submit?dep 11. O 04 points I Previous Answers GioCP2 23 P.060. My Notes Ask Your Teacher The radiation pressure from the Sun has a negligible effect on the orbit of a satellite, but it does pose a problem in terms of keeping a spacecraft pointing in the appropriate orientation. Consider the GOES-N geosynchronous weather satellite shown in the figure below. The satellite body is roughly a cube 2.0 m on a side with a 2.0-m by 4.0-m solar panel attached to the center of one face of the satellite's body. Assume the center of mass of the spacecraft is at the center of the cube. Take the intensity of the sun to be 1290 W/m GOES-N geosynchronous weather satellite. (a) Find the maximum force on the solar panel from the radiation pressure when the panel is perpendicular to the Sun's rays. 5.38e-7 N (b) Calculate the torque on the spacecraft about its center of mass when the Sun's rays are perpendicular to the solar panel, (c) Estimate the moment of inertia about the center of mass of the satellite, assuming uniform density and assuming the solar panel and other projections are negligible compared with its overall mass of 900 kg. kg m2 (d) What maximum rotational velocity, in degrees per hour, will the torque produce from a min exposure to full sunlight? Assume the initial angular speed is zero. deg/hr Need Help? Read it Talk to a Tutor Submit Answer save Progress Practice Another Version

Explanation / Answer

(a)

The force on each pannel

F= P/C= IA/C= I L h/C =1290 ( 4* 2)/ 3 * 10^8 = 3.44 * 10^-5 N

(b)

T = F d

= F ( l+ ls/2)

= 3.44 * 10^-5 N( 2+ 4/2)

=10.32 * 10^-5 N m

(c)

I = 1/6 * m l^2

= 1/6 * 900 * 2^2

=600 kg m^2

(d)

w= alpha t

= T/ Im * t

=10.32 * 10^-5 N m/600 * 44 * 60

=45.4 * 10^-5 rev/s ( 360 deg/ s) = 0.163 degree/s ( 3600 degree per hour) = 588.48 degre/ hr