1. Spherical mirrors. Object O stands on the central axis of a spherical mirror.
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Question
1. Spherical mirrors. Object O stands on the central axis of a spherical mirror. The table gives object distance p, the type of mirror, and focal distance f. Find the image distance i and the lateral magnification m of the object, including signs.
P (cm) Mirror f (cm) i (cm) m
+11 concave *19 ? ?
* Sign not given
Describe the image. (Select all that apply.)
Real
Virtual
Upright
Inverted
On the same side of the mirror as O
On the opposite side of the mirror
2. Spherical mirrors. Object O stands on the central axis of a spherical mirror. The table gives object distance p, the type of mirror, and focal distance f. Find the image distance i and the lateral magnification m of the object, including signs.
P (cm) Mirror f (cm) i (cm) m
+15 concave *12 ? ?
* Sign not given Describe the image. (Select all that apply.)
Real
Virtual
Upright
Inverted
On the same side of the mirror as O
On the opposite side of the mirror
3. Object O is located on the central axis 8 cm from a concave spherical mirror with focal distance f = 23 cm. Find the following.
a) The radius of curvature cm
(b) The image distance cm
(c) The lateral magnification
(d) Is the image real or virtual?
(e) Is the image inverted?
(f) Is the image on the same side of the mirror as O?
Yes
No
4. More mirrors. Object O stands on the central axis of a spherical or plane mirror. The table refers to the focal distance f, the object distance p, the image distance i, and the lateral magnification m. Fill in the missing information, including signs.
f (cm) p (cm) i (cm) m
-35 -19
Describe the mirror and image. (Select all that apply.)
Plane mirror
Concave mirror
Convex mirror
Real image
Virtual image
Upright image
Inverted image
Image on same side of mirror as O
Image on opposite side of mirror
5. Thin lenses. Object O stands on the central axis of a thin, symmetric lens. The table gives the object distance p, the type of lens and the focal distance f. Find the image distance i and the lateral magnification m of the object, including signs.
p (cm) Lens f (cm) i (cm) m
+13 diverging *7.5
* Sign not given Describe the image. (Select all that apply.)
Real
Virtual
Upright
Inverted
On the same side of the lens as O
On the opposite side of the lens
6. Thin lenses. Object O stands on the central axis of a thin, symmetric lens. The table gives the object distance p, the type of lens and the focal distance f. Find the image distance i and the lateral magnification m of the object, including signs.
P (cm) Lens f (cm) i (cm) m
+19 converging *3.0
* Sign not given Describe the image. (Select all that apply.)
Real
Virtual
Upright
Inverted
On the same side of the lens as O
On the opposite side of the lens
7. Figure (a) shows the basic structure of a human eye. Light refracts into the eye through the cornea and is then further redirected by a lens whose shape (and thus ability to focus the light) is controlled by muscles. We can treat the cornea and eye lens as a single effective thin lens as shown in Figure (b). A "normal" eye can focus parallel light rays from a distant object O to a point on the retina at the back of the eye, where processing of the visual information begins. As an object is brought close to the eye, however, the muscles must change the shape of the lens so that rays form an inverted real image on the retina as in Figure (c).
(a) Suppose that for the parallel rays of Figure (a) and Figure (b), the focal length f of the effective thin lens of the eye is 2.40 cm. For an object at distance p = 38.0 cm, what focal length f' of the effective lens is required for the object to be seen clearly? _________ Cm
(b) Must the eye muscles increase or decrease the radii of curvature of the eye lens to give focal length f'?
Increase
Decrease
Changing the radii doesn't affect the focal length
Insufficient information
8. Use principles of physics to solve the problem and then verify your answer using the simulation. Click-and-drag the light-blue dot at the tip of the dark blue arrow (the object) to re-size and/or re-position the object. Click-and-drag the light green dot at the center of the mirror/lens to move the mirror/lens left or right. Click-and-drag the red dot marking the focal point of the mirror/lens left or right to change the shape of the mirror/lens, and thus change its focal length. You have an optical instrument but you're not sure whether it is a mirror or a lens, so you use it to make some observations. (Please note that you're attempting to discover what optical instrument you have using a process of elimination. As such, your answers in each question are dependent upon your answers to the previous questions. i. e. Once an optical instrument is eliminated as a possibility, you should consider it eliminated for each question thereafter.)
When you place an object at a particular spot in front of your optical instrument you observe that the image of the object is smaller than the object itself. What could your optical instrument be? Select all the possibilities from the list below.
A concave mirror.
A convex mirror.
A plane mirror.
A converging lens.
A diverging lens.
When you then move the object toward the optical instrument a small distance you observe that the image of the object increases in size. What could your optical instrument be? Select all the possibilities from the list below.
A concave mirror.
A convex mirror.
A plane mirror.
A converging lens.
A diverging lens.
You also observe that the image created by the optical instrument is inverted compared to the object. What could your optical instrument be? Select all the possibilities from the list below.
A concave mirror
. A convex mirror.
A plane mirror.
A converging lens.
A diverging lens.
Finally, you observe that when you bring the object quite close to the optical instrument the image is upright and on the same side of the optical instrument as the object. What is your optical instrument?
A concave mirror.
A convex mirror.
A plane mirror.
A converging lens.
A diverging lens.
Explanation / Answer
1. 1/p+1/f=1/i
concave mirror, therefore, f will be negative
1/11+1/19=1/i
i= +2.6 cm
m=i/p
=0.236
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