1. If someone simply jumped at the vertical component of the velocity, how high

Question

1.    If someone simply jumped at the vertical component of the velocity, how high could they get?

2.    How does a pole vaulter convert all (or at least most) of the horizontal component of velocity to "vertical" energy (i.e. gravitational potential energy)? (Hint: See the picture below.)

3.    If all of the pole vaulter's kinetic energy was directly converted to gravitational potential energy, how high could the pole-vaulter's center of mass rise?

4.    Is this enough for success as a world class pole-vaulter - world standards are around 6 m for men, and 5 m for women?

5.    What velocity would be needed to reach world standards – around 6 m (men) or 5 m (women)?

Explanation / Answer

1) v2 = 82 + 22 = 68

v = 8.246 m/s

h = v2/2g = 8.2462/2x9.8 = 3.47 m

2) When pole vaulter run with a velocity, he has a kinetic energy. When he jumbs, it is converted to potential energy.At the maximum height, velocity becomes zero and he gets maximum gravitational potential energy.

3) h = v2/2g = 8.2462/2x9.8 = 3.47 m

4) No

5) v2 = 2gh

for men v2 = 2 x 9.8 x 6 =117.6

v = 10.8 m/s

for women

v2 = 2 x 9.8 x 5 =98

v = 9.9 m/s

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