An alpha particle (charge +2e) travels in a circular path of radius 0.5 m in a r

Question

An alpha particle (charge +2e) travels in a circular path of radius 0.5 m in a region with a magnetic field whose magnitude is 1.3 T. (The mass of an alpha particle is 6.65 times 10^-27 kg.) (a) Find the period of the alpha particle. mu s You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. (b) Find its speed. m/s You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question.) (c) Find its kinetic energy. MeV You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question.

Explanation / Answer

here,

charge on particle, q = 2*e

radius of path, r = 0.5 m

magnetic field, B = 1.3 T

mass of alpha particle, m = 6.65*10^-27 kg

Part B:
from mass spectrometer equation

m/q = B^2 * r^2 / (2 * V)

velocity, v = (B^2 * r^2)/(2 * m/q)

velocity, v = (1.3^2 * 0.5^2)/(2 * (6.65*10^-27)/(2*1.6*10^-19))

velocity, v = 1.02*10^7 m/s

Part a:

period, T = 2 * pi * r / v

period, T = 2 * pi * 0.5 / (1.02*10^7)

period, T = 3.08*10^-7 s or 0.308 us

Part c:
Kinetic energy = 0.5 * m * v^2

Kinetic energy = 0.5 * (6.65*10^-27) * (1.02*10^7)^2

Kinetic energy = 3.46*10^-13 J

1 J = 6.242*10^12 Mev

Kinetic energy = 2.16 MeV

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