An object is located 3.8 m in front of a plane mirror. The image formed by the m

Question

An object is located 3.8 m in front of a plane mirror. The image formed by the mirror appears to be A) 3.8 m in front of the mirror. B) on the mirror's surface. C) 1.9 m behind the mirror's surface. D) 38 m behind the mirrors surface. E) 1.9 m in front of the mirror. A10-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength 0.20 T. If the wire experiences a force of 0.06 N, what is the magnitude of the current moving through the wire? A) 4.0 A B) 5.0 A C) 2.0 A D) 1.0 A E) 3.0 A It takes 10. J of energy to move 2.0 C of charge from point A to point B What is the potential difference between points A and B? 20 V 5.0 V 0.50 V 0.20 V zero A typical public utility(power company) supplies electricity at an approximate cost of $1/kW h $100/kW h. 1.e/kW.h $10/kW h $10/kW h. The force of attraction between a +30.0 mu C and +94.0 mu C charge is 4.00 N. What is the separation between these two charges? 2.52 m 2.49 m 2.10 m 1.13 m 3.67 m A parallel-plate capacitor has plates of area 0.20 m^2 separated by a distance of 1.0 mm. What is this capacitor's capacitance? 4.2 times 10^-10 F 40 F 1.8 times 10^-9 F 3.5 times 10^-10 F 200 F A piece of plastic has a net charge of +200 mu C. How many more than electrons does this protons piece of plastic have? 1.25 times 1013 1.25 times 1019 0 2.50 times 1013 2.50 times 1019 A charge of 12 C passes through an electroplating apparatus in 20 min. What is the average current? 6.0 A 0.24 A 0.60 A 1.0 A 0.10 A Light of wavelength lambda = 480 nm passes through a pair of slits with separation 2.2 times 10^-5 m. What is the angle corresponding to the second bright fringe? 2.5^degree 1.5^degree 5.0^degree 4.3^degree 3.7^degree

Explanation / Answer

Given that object distance is do = 3.8 m

due to plane mirror,the virtual image is formed behind the mirror at a distance which is equal to object distance

So the answer is 3.8 m behind the mirror's surface

hence the correct choice is C)

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