We can use this equation to find the linear acceleration a_com, x of any body ro

Question

We can use this equation to find the linear acceleration a_com, x of any body rolling along an incline of angle theta with the horizontal. Note that the pull by the gravitational force causes the body to come down the ramp, but it is the frictional force that causes the body to rotate exceed f_s, max. then you eliminate the smooth rolling and the body slides down the ramp. Disks A and B are identical and toll across a floor with equal speeds. Then disk A rolls up an incline, reaching a maximum height h, and d than, less than, or equal to h? A uniform ball, of mass M = 6.00 kg and radius R, rolls smoothly from test down a ramp at angle theta = 30.0degree (Fig. 11-8) (a) The ball descends a vertical height h = 1.20 m to reach the bottom of the ramp. What is its speed at the bottom?

Explanation / Answer

By law of conservation of energy,

MEi = MEf

PEi= KEf

PEi= KErot + KEtrans

mgh = ½*I2 + ½*mv2

mgh = ½*2/5*mr2*(v/r)^2 + ½*m*v^2

gh = 1/5*v^2 + ½*v^2

gh=7/10*v^2

v=sqrt(10gh/7)

v=sqrt[(10*9.8*1.20)/7]

v=4.1m/s

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