FULL SCREEN PRINTERVERSION .BACx NEXT Chapter 35, Problem 021 In a double-slit e

Question

FULL SCREEN PRINTERVERSION .BACx NEXT Chapter 35, Problem 021 In a double-slit experiment the distance between slits is 4.6 mm and the slits are 1.4 m from the screen. Two interference patterns can be seen on the screen: one due to light of wavelength 440 nm, and the other due to light of wavelength 650 nm. What is the separation in meters on the screen between the 4 bright fringes of the two interference patterns? Number C Units the tolerance is +/-2% Click if you would like to show Work for this question: Open Show Work Question Attempts: o of s used SAVE FORLATER SUBMIT ANSWER Copyright 2000-2017 by John Wary & Sons, Inc. or related companies. All rights reserved

Explanation / Answer

m = 4, D = 1.4 m , d = 4.6 mm

lamda1 = 440 nm , lamda2 = 650 nm

Y = m*lamda*D/d

Y2 - Y1 = (mD/d)(lamda2 -lamda1)

= (4*1.4/0.0046)(650-440)*10^-9

= 0.00026 m = 0.26 mm

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