Chapter 15, Problem 014 Your answer is partially correct. Try again. A simple ha

Question

Chapter 15, Problem 014 Your answer is partially correct. Try again. A simple harmonic oscillator consists of a block of mass 2.90 kg attached to a spring of spring constant 170 N/m. When t 1.10 s, the position and velocity of the block are 0.136 m and v 3.400 m/s. (a) What is the amplitude of the oscillations? What were the (b) position and (c) velocity of the block at t 0 s? (a) Number TT-0.0133 unit (b) Number T- 0128 Unit Units T m/s (c) Numbe Click if you would like to Show Work for this question Open Show Work Question Attempts: 1 of 5 used SAVE FOR LATER SUBMIT ANSWER Copyright 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved.

Explanation / Answer

a )

= ( k / m )1/2

= ( 170 / 2.9 )1/2

= 7.65 rad/sec

x2 2 + v2 = A2 2

A2 = 0.1362 X 7.652 + 3.42 / 7.652

A = 0.464 m

b )

( t + ) = - tan-1 ( v / ( x ) )

= - tan-1 ( 3.4 / 7.65 X 0.136 )

= - 3.26

= - 11.675 rad

x = A cos ( t + )

x = 0.464 X cos ( 0 - 11.675 )

c )

v = - A sin ( t + )

v = - 7.65 X 0.464 X sin ( 0 - 11.675 )

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