A car is traveling at 50.0m/s in the negative x-direction and applies the brakes

Question

A car is traveling at 50.0m/s in the negative x-direction and applies the brakes to give an acceleration of 12.5m/s^2 over a distance x, and comes to a complete stop. What is the distance traveled by the car during the braking period? A)x = 100m B) x = 50m C) x = 25m D) x = 12.5m A simple pendulum consists of a mass m on the end of a string of length L. On Earth the pendulum has a period of T = 2s. If the pendulum is moved to Planet X with a gravitational acceleration one-fourth that of Earth's 9x = 9 Earth/4 what is the period of the same pendulum (same mass and length) on planet X? T = 4s B) T = 2 Squareroot 2s C) T = 2/Squareroot 2 s D) T = 1s

Explanation / Answer

14 ans

Given that

velocity v=50 m/s

acceleration a=12.5 m/s^2

now we find the distance to travel

distance S=v^2/2a=50^2/2*12.5=100 m

the correct option A

---------------------------------------------------------------------------------------------------------------------------------------------

15 ans

given that

time T1=2 sec

gravitational gx=gearth/4

basing on the concept of time period of simple of pendulum

now we find the new time period

T'/T=[g/gx]^1/2

T'/2=[g/g/4]^1/2

T'=4 sec

the correct option A

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.