Please help me with this physics problem. Thank you! The following constants can

Question

Please help me with this physics problem. Thank you!


The following constants can be used: ke = 8.99×109 Nm^2/C^2 qe = 1.6×10–19 C mp = 1.67×10^–27 kg me = 9.11×10^–31 kg eps0 = 8.85×10–12 C^2/(Nm^2) g = 9.80 m/s^2
A charge q1 = +5.57×10^–9 C is located 3.20 m from a charge of –2.80×10^–9 C. Find the magnitude of the electrostatic force exerted by one charge on the other.
Defined symbols: q1 first charge in C q2 second charge in C r distance between charges in meters The answer is F magnitude of the force in N
Hints for the problem:
Remember that the magnitude of a vector is always positive. Range of answers: 7.00×10^–9 N to 1.50×10^–8 N
Please help me with this physics problem. Thank you!


The following constants can be used: ke = 8.99×109 Nm^2/C^2 qe = 1.6×10–19 C mp = 1.67×10^–27 kg me = 9.11×10^–31 kg eps0 = 8.85×10–12 C^2/(Nm^2) g = 9.80 m/s^2
A charge q1 = +5.57×10^–9 C is located 3.20 m from a charge of –2.80×10^–9 C. Find the magnitude of the electrostatic force exerted by one charge on the other.
Defined symbols: q1 first charge in C q2 second charge in C r distance between charges in meters The answer is F magnitude of the force in N
Hints for the problem:
Remember that the magnitude of a vector is always positive. Range of answers: 7.00×10^–9 N to 1.50×10^–8 N
Please help me with this physics problem. Thank you!


The following constants can be used: ke = 8.99×109 Nm^2/C^2 qe = 1.6×10–19 C mp = 1.67×10^–27 kg me = 9.11×10^–31 kg eps0 = 8.85×10–12 C^2/(Nm^2) g = 9.80 m/s^2
A charge q1 = +5.57×10^–9 C is located 3.20 m from a charge of –2.80×10^–9 C. Find the magnitude of the electrostatic force exerted by one charge on the other.
Defined symbols: q1 first charge in C q2 second charge in C r distance between charges in meters The answer is F magnitude of the force in N
Hints for the problem:
Remember that the magnitude of a vector is always positive. Range of answers: 7.00×10^–9 N to 1.50×10^–8 N
Please help me with this physics problem. Thank you!


The following constants can be used: ke = 8.99×109 Nm^2/C^2 qe = 1.6×10–19 C mp = 1.67×10^–27 kg me = 9.11×10^–31 kg eps0 = 8.85×10–12 C^2/(Nm^2) g = 9.80 m/s^2
Please help me with this physics problem. Thank you!


The following constants can be used: ke = 8.99×109 Nm^2/C^2 qe = 1.6×10–19 C mp = 1.67×10^–27 kg me = 9.11×10^–31 kg eps0 = 8.85×10–12 C^2/(Nm^2) g = 9.80 m/s^2
A charge q1 = +5.57×10^–9 C is located 3.20 m from a charge of –2.80×10^–9 C. Find the magnitude of the electrostatic force exerted by one charge on the other.
Defined symbols: q1 first charge in C q2 second charge in C r distance between charges in meters The answer is F magnitude of the force in N
Hints for the problem:
Remember that the magnitude of a vector is always positive. Range of answers: 7.00×10^–9 N to 1.50×10^–8 N

Explanation / Answer

force=K*q1*q2/r^2

putting the value

we get force

F=1.37*10^(-8) N

it will be off attractive nature as charge are of opposite sign

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