I got the first part, but I\'m struggling with the second part. A finite line of

Question

I got the first part, but I'm struggling with the second part.

A finite line of charge with linear charge density = 2.15x 106 C/m, and length L = 0.786 m is located along the x axis (from x = 0 to x = L). A point charge of q--666 x 107 C is located at the point xo = 1.70 m, yo = 4.25 m. Find the electric field (magnitude and direction as measured from the +x axis) at the point P which is located along the x axis at xp 10.5 m The Coulomb force constant k = 1/(4TEo) = 8.998 109 N·m2/C2 Number E= | | 148.9 N/ C Number Xo = yo XP

Explanation / Answer

On the road to calculate resultant electric field E, you had calculated Ex and Ey (electric fields in x and y direction or I and j components).

To calculate direction, simply use the formula, theta = tan-1(Ey/Ex)

Above will be your direction. Make sure your calculator is in degree mode not in radian mode

Feel free to ask any doubt and if helpful, do rate, good luck and wish you success...

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