Chapter 21, Problem 008 In the figure three identical conducting spheres initial

Question

Chapter 21, Problem 008 In the figure three identical conducting spheres initially have the following charges: sphere A, 3Q; sphere B, -6Q; and sphere C, 0. Spheres A and B are fixed in place, with a center-to-center separation that is much larger than the spheres. Two experiments are conducted. In experiment 1, sphere C is touched to sphere A and then (separately) to sphere B, and then it is removed. In experiment 2, starting with the same initial states, the procedure is reversed: Sphere C is touched to sphere B and then (separately) to sphere A, and then it is removed. What is the ratio of the electrostatic force between A and B at the end of experiment 2 to that at the end of experiment 1? Number the tolerance is +/-596 Click if you would like to Show Work for this question: Open Show Work Units

Explanation / Answer

when two sphere are touched and removed then total charge get divided inbetween them.

1. A and C : total charge = 0 + 3 Q = 3 Q

charges , qA = qC = 3Q/2 = 1.5Q

now C is touched to B. total charge = 1.5Q - 6Q = -4.5Q

qB = qC = - 4.5Q/2 = - 2.25 Q

F1 = k qA qB / d^2 = 3.375 k Q / d^2

2. now B and C: total charge = 0 + -6Q = - 6Q

qB = qC = - 6 Q/2 = - 3 Q

now C and A. total charge = - 3Q + 3 Q = 0

qC = qA = 0

F2 = 0

ratio = F2 / F1 = 0

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