(9%) Problem 6: A charge Q = 42.9 C sits somewhere inside a cube of side length
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(9%) Problem 6: A charge Q = 42.9 C sits somewhere inside a cube of side length l = 1.2 cm 33% Part (a) What is the electric flux in Nm2/C through the surface of the cube? 33% Part (b) Now assume the charge is at the very center of the cube. What is the flux through one of the faces, in Nm2/C? 33% Part(c) A regular polyhedron is a three-dimensional object whose faces are all identical regular polygons-that is, all their and edges are the same. A cube is an example for n = 6 faces. If we put our charge at the center of a regular polyhedron with n faces, giv expression for the flux through a single face. Grade Summ Deductions Potential Submissions Attempts rem (190 per atten detailed view 0 BACKSPACE DEL CLEAR Submit Hint I give up!Explanation / Answer
a) Electric flux is phi_E = q_inside/ eo = (42.9*10^-6)/(8.85*10^-12) = 4.85*10^6 Nm^2/C
eo is the permittivity of free space
b) Since the cube has six faces then
flux through one of the face is phi_E = (q_inside/(6*eo)) = (42.9*10^-6)/(6*8.85*10^-12) = 8.07*10^5 Nm^2/C
phi_S(n) = Q/(n*eo)
eo is the epsilon_0
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