(9%) Problem 4: Suppose we want to calculate the moment of inertia of a 62.5 kg

Question

(9%) Problem 4: Suppose we want to calculate the moment of inertia of a 62.5 kg skater, relative to a vertical axis through their center of mass 50% Part (a) First calculate the moment of inertia (in kg-m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.15 m. - ** 50% Part (b) Now calculate the moment of inertia of the skater (in kgm2) with their arms extended by assuming that each arm is 5% if the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.875 m long rods extending straight out from their body being rotated at the ends Grade Summary Deductions Potential 1= 2.30 1% 99% sin cotanasin0 atanOacotan) si tanO t ( acosO sinhO Submissions Attempts remaining: 4 (190 per attempt) detailed view 78 9HOME 1% cosh0tan0 coho Degrees Radians 0 END VO BACKSPACE |DEL| CLEAR | Submit Hint Feedback Hints: 1 % deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback Submission History All Date times are displayed in Eastern Standard Time Red submission date times indicate late work Date Time Answer Hints Feedback I 2.30 I- 2.3 1 Jul 26, 2018 1:39 PM Note: Feedback not accessed.

Explanation / Answer

B)

Mass of body, m_rod = 0.05 x 62.5 = 3.125 kg

Moment of inertia, I = 0.5 MR^2 + 2(0.333 mr^2)

I = (0.5 x 62.5 x 0.15^2) + 2(0.333 x 3.125 x 0.875^2)

I = 2.296 kgm^2

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