ent FULL SCREEN PRINTER VERSION BACK NEXT Chapter 22, Problem 016 The figure sho
ID: 1574350 • Letter: E
Question
ent FULL SCREEN PRINTER VERSION BACK NEXT Chapter 22, Problem 016 The figure shows a plastic ring of radius R = 50.1 cm. Two small charged beads are on the ring: Bead 1 of charge +2.09 C is fixed in place at the left side; bead 2 of charge +6.04 C can be moved along the ring. The two beads produce a net electric field of magnitude E at the center of the ring. At what (a) positive and (b) negative value of angle should bead 2 be positioned such that E 2.03 × 105 N/C? Ring Bead 2 Bead 1 Units (a) Number (b) Number ( -) Units Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSExplanation / Answer
By law of cosines,
E² = [k(q1)/R²]² + [k(q2)/R²]² - 2[k(q1)/R²][k(q2)/R²]cos
(2.03e5 N/C)² R^4 / k² = (q1)² + (q2)² - 2(q1)(q2)cos
(2.00e5 N/C)² (0.501 m)^4 / (9.00e9 N-m²/C²)² = (2.09e-6 C)² + (6.04e-6 C)² - 2(2.09e-6 C)(6.04e-6 C)cos
cos = 0.385
= ±67.36°
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