An Australian emu is running due north in a straight line at a speed of 13.0 m/s

Question

An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 9.80 m/s in 3.70 s. (a) What is the magnitude and direction of the bird's acceleration? (b) Assuming that the acceleration remains the same, what is the bird's velocity after an additional 2.20 s has elapsed? (a) N (b) N Click if you 0.864 m/s 2 9.6592 m/s would like to Show Work for this question: Your answer is partially correct. Try again. For each of the three pairs of positions listed in the following table, determine the magnitude and direction (positive or negative) of the displacement. (a) Displacement- Number 3.9 Units (b) Displacement Number 3.8 (c) Displacement Number 10.2 Click if you would like to Show Work for this question: Open Show Work Unitsm Units m

Explanation / Answer

a] Initial velocity of the emu = u = 13 m/s

final velocity = v = 9.8 m/s

t = 3.7 s

use v = u + at

9.8 = 13 + a(3.7)

=> a = - 0.865 m/s2

so, the magnitude of acceleration is: |a| = 0.865 m/s2

and the direction of bird's acceleration is due South since Emu is decelerating.

b] t' = 3.7 + 2.2 = 5.9s

v = 13 - 0.865(5.9) = 7.897 m/s

This is emu's velocity after additional 2.2 seconds.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.