Three identical point particles that have charge q are at the vertices of an equ

Q: Three identical point particles that have charge q are at the vertices of an equ

a) V = 3*k*q/a = 3*9*10^9*2.4*10^-6/0.645 = 1.00*10^5 N/c b) V = 3*k*q/(sqrt(2)*a) = 3*9*10^9*2.4*10^-6/(sqrt(2)*0.645) = 7.10*10^4 N/c c) Answers to part a and b do not change because. The distance from point to the charges remains same.

ID: 1574798 • Letter: T

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Three identical point particles that have charge q are at the vertices of an equilateral triangle that is circumscribed by a circle of radius a that lies in the z = 0 plane and is centered at the origin. The values of q and a are +2.40 HC and 64.5 cm, respectively. (Assume the potential is zero very far from all charges.) what is the electric potential at kV (b) What is the electric potential at the point on the z axis at z- a? (c) How would your answers to Parts (a) and (b) change if the charges were still on the circle but one is no longer at a vertex of the triangle? Explain your answer. This answer has not been graded yet. eBook

Explanation / Answer

a) V = 3*k*q/a

= 3*9*10^9*2.4*10^-6/0.645

= 1.00*10^5 N/c

b) V = 3*k*q/(sqrt(2)*a)

= 3*9*10^9*2.4*10^-6/(sqrt(2)*0.645)

= 7.10*10^4 N/c

c) Answers to part a and b do not change because.

The distance from point to the charges remains same.

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Three identical point particals that have charge q are at thevertices of an equi

Three identical point particles that have charge q are at the vertices of an equ

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Three identical point particles that have charge q are at the vertices of an equ

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