Suppose you want to determine the electric field in a certain region of space. Y

Question

Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field.

(a) The object has a charge of +11.0 µC and the instrument indicates that the electric force exerted on it is 39.0 µN, due east. What are the magnitude and direction of the electric field?
E =   ---Select--- N C J N/C  ---Select--- due south due east due north due west

(b) What are the magnitude and direction of the electric field if the object has a charge of -9.0 µC and the instrument indicates that the force is 22.0 µN, due west?
E =   ---Select--- N C J N/C  ---Select--- due south due north due east due west

Explanation / Answer

a) charge q = + 11.0 x 10-6 C and electric force F = 39.0 x 10-6 N

magnitude of electric field E = F/q = 39.0 x 10-6 / 11.0 x 10-6 = 3.55 N/m, due East since it is a positive charge

b) q = - 9.0 x 10-6 C and F = 22.0 x 10-6 N

hence E = F/q = 22.0 x 10-6 /   9.0 x 10-6

= 2.44 N/m due East since it is a negative charge

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