I need help with every part please explain Problem 23.63 Constants Part A Cathod

Question

I need help with every part please explain Problem 23.63 Constants Part A Cathode-ray tubes (CRTs) are often found in osoilloscopes and computer monitors. In the figure Figure 1)an electron with an initial speed of 6.30*10% m/s is projected along the axis midway between the deflection plates of a cathode-ray tube. The potential difference between the two plates is 18.0 V and the lower plate is the one at higher potential What is the magnitude of the force on the olectron when it is behween the plates? Figure 1 of 1 Submit Previous Answers Request Answer X Incorrect: Try Again; 19 attempts remaining 2.0 cm Part B K6.0 cm 12.0cm What is the direction of the force on the electron when it is between the plates? Upward Downward

Explanation / Answer

a) electric field, E= v/d= 18/(2/100)= 900N/c

force experienced= eE= 1.6*10^-19*900= 1440*10^-19

b) accelerated along downwards

c) a= f/m= 1440*10^-19/(9.1*10^-31)= 1.582*10^14m/s2

d) directed downwards

e) t= 0.06/6.3*10^6= 9.524*10^-9 s

d= 0.5*a*t*t= 0.5 *1.582*10^14*(9.524*10^-9)^2 = 7.175*10^-3 m

f) theta= tan-1(1.507/6.3)= 13.453 degrees

plz rage

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