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Aproton entersparalel plate cioacter trawing to n at a speed of , 278 x 10,mh as

ID: 1575186 • Letter: A

Question

Aproton entersparalel plate cioacter trawing to n at a speed of , 278 x 10,mh asshow, n "te ng "The datance between the two plate. " 1.5, on me poton enten ae ai acea Salt ay-me-the tsp plar and be bothom glate; that s a dstancer-0.705 em from each plate, as shown in the figure The capacieor has a 29510N/C unfiorm electnec field between the pistes thst poirnts dowrward from the bop plate te the botitam plete eglecting graiational orces what horial detiance does the proton treverse before the proton hets the bottom plste

Explanation / Answer

v0x = 1.278 x 10^5 m/s


electric force, Fe = q E

a = Fe / m = q E / m downwards

a = (1.6 x 10^-19) (2.95 x 10^-4 ) / (1.67x 10^-27)

a = 28263.5 m/s^2

in vertical direction,

y = v0y t + ay t^2 / 2

0.00795 = 0 + (28263.5) t^2 / 2

t = 7.5 x 10^-4 sec


x = (v0x) t = 95.9 m

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