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Apps D UlOnlineUnited States Postal L Two tail hypothesis t (12/2)-6; (6/3.84 10

ID: 1731479 • Letter: A

Question

Apps D UlOnlineUnited States Postal L Two tail hypothesis t (12/2)-6; (6/3.84 10 8) (3.5 106 (12/2)-6; (6/3.84 108)*(3.5 1046)- 7. A candle is placed 12cm away from a concave lens. The lens produces a virtual image -24cm away from the lens. If the object is moved back to 16cm from the lens, determine the position of the image with respect to the lens? All distances are measured from a reference surface, such as a wavefront or a refracting surface-the lens. Distances to the left of the surface are negative. Heights above the axis of symmetry of the lens are positive, below are negative. Use this interactive figure to verify your calculations! Click on the Understand tab at the right bottom to change the distances Oobject lens p and limage-lens q! A)-5.3cm. B)-24.5cm C)+9.2cm. D)-15.4cm. Use 3 sig figs: 0.00234 OR 2.34E-3, use capital El Distance: xint es v(t)dt rarn

Explanation / Answer

First case,
object distance, u = 12 cm
Image distance, v = - 24 cm
1/(-f) = 1/u + 1/v
= 1/12 - 1/24
= 0.0417
f = -1/0.0417
= - 24 cm

In the second case,
u = 16 cm
1/v = 1/(-f) - 1/u
= - 1/24 - 1/16
= - 0.1042
v = - 9.6 cm

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