Two forces, F 1 and F 2, act at a point. F 1 has a magnitude of 8.40 N and is di

Question

Two forces, F 1 and F 2, act at a point. F 1 has a magnitude of 8.40 N and is directed at an angle of 57.0 above the negative x axis in the second quadrant. F 2 has a magnitude of 5.80 N and is directed at an angle of 52.6 below the negative xaxis in the third quadrant.

1.

What is the x component of the resultant force?

Express your answer in newtons.

2.

What is the y component of the resultant force?

Express your answer in newtons.

3.

What is the magnitude of the resultant force?

Express your answer in newtons.

Explanation / Answer

1) x component of resultant Force is Fnet,x = -F1*cos(57) - F2*cos(52.6)

Fnet,x = (-8.4*cos(57))-(5.8*cos(52.6)) = -8.09 N

2) y component of resultant Force is Fnet,y = F1*sin(57) - F2*sin(52.6)

Fnet,y = (8.4*sin(57))-(5.8*sin(52.6)) = 2.44 N

3) magnitude of resultant force is Fnet = sqrt(8.09^2+2.44^2) = 8.45 N

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