Find the magnitude and the direction of the electric field this combination of c
ID: 1576639 • Letter: F
Question
Find the magnitude and the direction of the electric field this combination of charges produces at point P, which lies 6.00 cm from the -q2 charge measured perpendicular to the line connecting the three charges. Assume that q1=5.00uc and q2=2.45uc.
Explanation / Answer
angle made by the line from p to q1 at point P = theta = tan^-1(8/6) = 53.13
r1 = sqrt(8^2+6^2) = 10 cm = 0.1 m
E1x = -k*q1*costheta/r1^2 = -9*10^9*5.5*10^-6*cos53.13/0.1^2
E1x = -29.7*10^5 N/C
E2x = -k*q2/x^2 = -9*10^9*2.45*10^-6/0.06^2 = -61.25*10^5 N/C
Ex = E1x + E1x + E2x = -120.65*10^5 N/C = -1.21*10^7 N/C <<---------ANSWER
part A
magnitude E = 1.21*10^7 N/C <<---------ANSWER
part B
direction = toward -q2
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