Additional Materials

Question

2.–/0.5 pointsHRW10 2.P.025. Ask Your Teacher My Notes Question Part Points Submissions Used An electric vehicle starts from rest and accelerates at a rate of 3.0 m/s2 in a straight line until it reaches a speed of 10 m/s. The vehicle then slows at a constant rate of 1.0 m/s2 until it stops. (a) How much time elapses from start to stop?
s

(b) How far does the vehicle travel from start to stop?
m

• Section 2.4
• Powers of Ten

2.–/0.5 pointsHRW10 2.P.025. Ask Your Teacher My Notes 2.–/0.5 pointsHRW10 2.P.025. Ask Your Teacher My Notes Ask Your Teacher Question Part Points Submissions Used An electric vehicle starts from rest and accelerates at a rate of 3.0 m/s2 in a straight line until it reaches a speed of 10 m/s. The vehicle then slows at a constant rate of 1.0 m/s2 until it stops. (a) How much time elapses from start to stop?
s

(b) How far does the vehicle travel from start to stop?
m Additional Materials

• Section 2.4
• Powers of Ten

Question Part Points Submissions Used Question Part Points Submissions Used Question Part Points Submissions Used Question Part Points Submissions Used Question Part Points Submissions Used An electric vehicle starts from rest and accelerates at a rate of 3.0 m/s2 in a straight line until it reaches a speed of 10 m/s. The vehicle then slows at a constant rate of 1.0 m/s2 until it stops. (a) How much time elapses from start to stop?
s

(b) How far does the vehicle travel from start to stop?
m Additional Materials

• Section 2.4
• Powers of Ten

An electric vehicle starts from rest and accelerates at a rate of 3.0 m/s2 in a straight line until it reaches a speed of 10 m/s. The vehicle then slows at a constant rate of 1.0 m/s2 until it stops. (a) How much time elapses from start to stop?
s

(b) How far does the vehicle travel from start to stop?
m Additional Materials

• Section 2.4
• Powers of Ten

(a) How much time elapses from start to stop?
s

(b) How far does the vehicle travel from start to stop?
m Additional Materials

• Section 2.4
• Powers of Ten

Question Part Points Submissions Used

Explanation / Answer

(a)

Let, time taken untill vehicle reaches speed 10 m/s = t1

from kinematic equation,

v = u + at

t1 = 10 / 3 = 3.33 s

Time taken when it slows untill stops,

t2 = 10 / 1 = 10 s

Time elapsed from start to stop,

t = 3.33 + 10

t = 13.33 s

(b)

Displacement of vehicle untill reaches speed 10 m/s,

d1 = ut + (1/2)at^2

d1 = 0 + (1/2)*3*(3.33)^2 = 33.33 m

Displacement when it slows untill stops,

d2 = ut - (1/2)at^2

d2 = 10*10 - (1/2)*1*10^2 = 50 m

Total displacement from start to stop,

D = 33.33 + 50

D = 83.33 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.