#2 The circuit above contains a battery with negligible internal resistance, a c

Question

#2 The circuit above contains a battery with negligible internal resistance, a closed switch S, and three resistors, each with a resistance of R or 2R. Rank the currents in the three resistors from greatest to least. If two resistors have the same current, give them the same ranking. a) b) Rank the voltages across the three resistors from greatest to least. If two resistors have the same voltage across them, give them the same ranking. For parts (c) through (e), use -12 V and R-200 . c) Calculate the equivalent resistance of the circuit. d) Calculate the current in resistor Rc e) The switch S is opened, resistor Rs is removed and replaced by a capacitor of capacitance 2.0x10 F, and the switch S is again closed. Calculate the charge on the capacitor after all the currents have reached their final steady-state values

Explanation / Answer

(A) current through Ra will be equal to the current through battery. then it got divided into Rb and Rc.

and resistor with greater resistance will have less current.

Ra > Rc > Rb

(B ) Rb and Rc are connected in parallel so they will have same voltage but less than Ra.

Ra > Rb = Rc

(C) Rb and Rc are in parallel,

1/R' = 1/200 + 1/400

R' = 133.33 ohm

now R' and Ra are in series,

Req = R' + Ra = 533.33 ohm

(D) I_battery = 12/Req = 0.0225 A

through Rc = 0.0225 x (2R) / (R + 2R)

= 0.015 A

(E) then I = 12/(400 + 200) = 0.02 A

Vc = 0.02 x 200 = 4 volt

Q = C Vc = (2 x 10^-6) (4)

Q = 8 x 10^-6 C

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