(10%) Problem 5: A truck travels a distance d= 23.5 m in the positive x-directio
ID: 1577716 • Letter: #
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(10%) Problem 5: A truck travels a distance d= 23.5 m in the positive x-direction in a time of t1 = 20.5 s. The truck immediately brakes and comes to rest in t2 = 9 s Randomized Variables d= 23.5 m t120.5 s t,-9s ©theexpertta.com 25% Part (a) What was the truck's average velocity in the horizontal direction. 1n meters per second, during t? Grade Summary Deductions Potential 0% 100% an sin0 cotan0asin acos0 atan0 acotan sinhO cosh0 tanh cotanh0 co tan Submissions Attempts i (090 per attempt) detailed view *12 3 END Degrees Radians NO Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. 25% Part (b) what was the acceleration, in meters per second squared, during time interval t1, assuming the truck started from rest and moved with a constant acceleration? 25% Part (c) What was the truck's instantaneous velocity in the horizontal direction, in meters per second, when it began braking? - 25% Part (d) Using the result from part (c), what was the truck's horizontal component of acceleration, in meters per second squared, during the braking period?Explanation / Answer
(A) average velocity = displacement / time
= 23.5 / 20.5
= 1.15 m/s
(B) d = v0 t1 + a1 t1^2 / 2
23.5 = 0 + a1 (20.5^2)/2
a1 = 0.112 m/s^2
(C) v = v0 + a1 t1 = 2.29 m/s
(D) vf = vi + a t
0 = 2.29 - a(9)
a = - 0.25 m/s^2
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