Three charged marbles are glued to a nonconducting surface and are placed in the

Question

Three charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are 91 = 5.70 C, 92 = 1.86 c, and q3--1. 97 pC. Marble q1 is a distance r1 = 3.00 cm to the left of the marble 92, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance r, 1.00 cm to the left of the center, marble. N/C 71 92 43 observation point Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of 3.73 HC, calculate magnitude and direction of the force on it. magnitude direction Select

Explanation / Answer

due to q1:

E1 = k q1 / (r1 - r')^2

E1 = ( 9x 10^9) (5.70 x 10^-6) / (0.03 - 0.01)^2

E1 = 128.25 x 10^6 N/C to the right

due to q2:

E2 = ( 9x 10^9) (1.86 x 10^-6) / (0.01)^2  

E2 = 167.4 x 10^6 N/C to the left

due to q3:

E3 = ( 9x 10^9) (1.97 x 10^-6) / (0.03^2)

E3 = 19.7 x 10^6 N/C to the right

E = E1 - E2 + E3 = - 19.45 x 10^6 n/ C

Magnitdue = 19.45 x 10^6 N/C ....Ans

F = q E = (3.73 x 10^-6) (19.45x 10^6)

f = 72.5 N ......Ans

direction-> to the left Or along -ve x axis

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