My Notes O Ask Your Teacher 12. -3 points SerCP8 17.P.057.ssm You are cooking br

Question

My Notes O Ask Your Teacher 12. -3 points SerCP8 17.P.057.ssm You are cooking breakfast for yourself and a friend using a 1280 W waffle iron and a 490 W coffeepot. Usually, you operate these appliances from a 110 V outlet for 0.500 h each day (a) At 12 cents per kWh, how much do you spend to cook breakfast during a 30.0 day period? (b) You find yourself addicted to waffles and would like to upgrade to a 2560 W waffle iron that will enable you to cook twice as many waffles during a half-hour period, but you know that the circuit breaker in your kitchen is a 20 A breaker. Can you do the upgrade? Give the current that this new waffle iron (along with the coffee pot) draws to support your answer. Need Help? Talk to a Tutor

Explanation / Answer

a)

No. of hours appliances operate in 30 days = 0.5 * 30 = 15 hours

Energy=Power * time

Energy consumed for 30 days = 1280 W * 15 h + 490 W * 15 h = 26.55 KWh

Rate = 0.12 $ for 1 Kwh

for 26.55 Kwh , cost = 0.12 * 26.55 $ = 3.186 $

b)

No, we can't do the upgrade

REASON:-

Calculating Current in new waffle iron ,

let I be the current drawn by the waffle iron and V be the voltage

Power = V * I ,

I = Power / V

I = 2560 / 110 = 23.27 Amp

Current drawn is greater than 20A( = 23.27A ), hence circuit breaks and upgrade cant be done to cook twice the amount of waffles.

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