As shown in the figure below, a green bead of mass 60 g slides along a straight
ID: 1580775 • Letter: A
Question
As shown in the figure below, a green bead of mass 60 g slides along a straight wire. The length of the wire from pointto point is 0.700 m, and pointis 0.400 m higher than point B. A constant friction force of magnitude 0.035 0 N acts on the bead. (a) If the bead is released from rest at point hat is its speed at point m/s (b) A red bead of mass 60 g slides along a curved wire, subject to a friction force with the same constant magnitude as that on the green bead. If the green and red beads are released simultaneously from rest at point , which bead reaches point with a higher speed? O the green bead O the red bead Oboth beads arrive with equal speed Explain.Explanation / Answer
Since B is 0.4m below A, the bead has lost 'mgh' potential energy and picked up that much KE. But then in sliding down the wire it has lost F x d energy to friction. Let's sum these...
dU = mgh - Fd
dU = 0.060kg (9.81m/s^2) 0.400m - 0.0350N *0.700m
dU = 0.211 J
dU = KE = 0.5 m v^2
v^2 = 2 KE / m
v = sqrt(2 KE / m)
v = sqrt(2 (0.211J) / (0.060kg)
v = 2.65 m/s
b) Both beads arrive at same speed.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.