In the figure, a conducting rod of length L = 31.0 cm moves in a magnetic field

Question

In the figure, a conducting rod of length L = 31.0 cm moves in a magnetic field B of magnitude 0.410 T directed into the plane of the figure. The rod moves with speed v = 7.00 m/s in the direction shown

Part A- When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?

b

Part B- What is the direction of the electric field in the rod?

from b to a

Part C- When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod? Express your answer in volts per meter to at least three significant figures.

Part D- Which point, a or b, has a higher potential?

Part E- What is the magnitude Vba of the potential difference between the ends of the rod?

Part F- What is the magnitude E of the motional emf induced in the rod?

b

Part B- What is the direction of the electric field in the rod?

from b to a

Part C- When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod? Express your answer in volts per meter to at least three significant figures.

Part D- Which point, a or b, has a higher potential?

Part E- What is the magnitude Vba of the potential difference between the ends of the rod?

Part F- What is the magnitude E of the motional emf induced in the rod?

Explanation / Answer

when the rod is in motion charges experience magnetic force in presence of magnetic field and according to Force(magnetic) = q*[VxB]

if velocity is on -ve y-axis and field inside the plane then by Right hand Screw rule positive charges experience force towards point P and negative charges accumulate at point A and hence naturally their is attractive columbic force between charges so in steady condition these forces balance each other and Hence

A) B

C) q*v*B = q*E

E = v*B

E = 7*0.41 =2.87 V/m

E)emf V = E*d

d = 31cm = 0.31m

V = 2.87 * 0.31

V = 0.8897 V

F) same as answer to qn E

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