In the figure, a conducting rod of length L = 31.0 c m moves in a magnetic field

Question

In the figure, a conducting rod of length L = 31.0cm moves in a magnetic field B? of magnitude 0.550T directed into the plane of the figure. The rod moves with speed v = 7.00m/s in the direction shown. (Figure 1)

http://session.masteringphysics.com/problemAsset/1011317/15/yf_Figure_29_32.jpg

When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?

E= ____________ V/m

In the figure, a conducting rod of length L = 31.0cm moves in a magnetic field B? of magnitude 0.550T directed into the plane of the figure. The rod moves with speed v = 7.00m/s in the direction shown. (Figure 1) When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod? E= V/m

Explanation / Answer

Magnetic field B = 0.550 T

speed v = 7.00 m/s

E = B v

E = 0.550 * 7

= 3.85 N/C = 3.85 V/m

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b) The potential difference is Vba = E L

= (3.85)(0.31)

= 1.19 V

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c) e = v l B

= (7m/s) (0.550) (0.31)

= 1.19 V

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