/edugen.wileyplus.com/edugen/student/mainfr.uni WileyPLUS: MyWileYPLUS Cutnell,

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/edugen.wileyplus.com/edugen/student/mainfr.uni WileyPLUS: MyWileYPLUS Cutnell, Physics,10e Physics 201 and 202 (Physics 201 and 20 Assignment Gradebook ORION Downloadable eTextboolk nt MESSAGE MY INSTRUCTOR FULL SOREEN PRINTER VERSION BACK Chapter 08, Problem 41 Your answer is partially correct. Try again. A baseball pitcher throws a baseball horizontally at a linear speed of 50.7 m/s. Before being caught, the baseball travels a horizontal distance of 18.9 m and rotates through an angle of 52.2 rale The baseball has a radius of 3.34 cm and is rotating about an axis as it travels, much like the earth does. What is the tangential speed of a point on the equator" of the baseball? UnitsTm/s the tolerance is +/-2% SHOW HINT LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Drew SAVE FOR LATER Question Attempts: Unlimited

Explanation / Answer

First find the flight time.

time = t = distance/speed = 18.9/50.7 s = 0.372 s

Now determine the number of rotations of the baseball.
number of rotations = n = 52.2 rads/(2*pi) = 8.30

And now the time for one rotation:
time for a rotation = T = t/n = 0.372/8.3 = 0.0448 s

The circumference of the baseball is:
C = 2*pi*R where R is 3.34 cm = 0.0334 m
C = 0.2098 m

The tangential speed is then the circumference divided by the time it takes to complete one rotation.
speed = C/T
speed = 0.2098/0.0448 = 4.683 m/s

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