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Chapter 21, Problem 53 Suppose in the drawing that I1 12 11.0 A and that the sep

ID: 1580947 • Letter: C

Question

Chapter 21, Problem 53 Suppose in the drawing that I1 12 11.0 A and that the separation between the wires is 0.0281 m. By applying an external magnetic field (created by a source other than the wires) it is possible to cancel the mutual repulsion of the wires. This external field must point along the vertical direction. (a) Does the external field point up or down? (b) What is the magnitude of the external field? Wire 1 Wire 2 Repulsion (a) The external field points (b) Number the tolerance is +/-2% Units

Explanation / Answer

a)

The field at each wire cretes by the other wire is up so the external field must be DOWN

b)

Its magnitude = o*I/2r

= 4 × 107.*11/0.0281

= 4.919x10^-4T

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