Question 13 As a musician warms up a wind instrument to play, the temperature of

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Question 13 As a musician warms up a wind instrument to play, the temperature of the air in the instrument increases What is the result of this change on the fundamental for the instrument? AAn increase in both frequency and wavelength B) An increase in frequency and a decrease in wavelength C) An increase in both wave speed and frequency. D) An increase in wave speed and a decrease in frequency. E) An increase in wave speed and a decrease in wavelength Question 14 An organ pipe with both ends open has a fundamental frequency of 400 Hz. If one end of this pipe is now closed the fundamental frequency will now be: A) 100 Hz B)200 400 Hz D) 800 Ha E) 1600 Hz Question 15 An air column in a tube that is open at one end and closed at the other is 0.8 m long and produces a fundamental note of frequency 100 Hz when the tube is struck and a standing wave is set up. What are the frequencies of the first two overtones? A)100 and 200 Hz B) 100 Hz and 300 Hz C)200 Hz and 300 50 200 Hz and 400 Hz E) 300 Hz and 500 Hz Question 16 Two speakers output the same tone in the same phase. A person sitting in a chair across the room at the same distance from both speakers hears the tone very well. However, when the person moves the chair to the right so that she is one half meter closer to one speaker than the other, she is not able to hear the tone very well. What is the wavelength of the tone produced by the speakers? A) 0.25 m 0.50 m 0.75 m D) 1.0 m E) 1.5 m Question 17 ch electromagnetic wave has the highest frequency? amma rays B) Infrared radiation C) Radio waves

Explanation / Answer

Q13.

The increase in temperature of the air in the instrument causes an increase in the speed of sound, which raises the fundamental frequency.

Q14.

Fundamental frequency of organ pipe open at both ends is

f=v/2L

And, if one end is closed then it is

f=v/4L

So it will be half of the first case,

f=200Hz.

Q15.

General form of frequency in this type of organ pipe is

f= (2n+1)v/4L

So it is a multiple of (2n+1) of fundamental frequency.

First overtone n=1 and second overtone n=2

So it will be,

300 and 500 Hz

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