a billiard ball is shot west at 2.80 m/s. A second, identical billiard ball is s

Question

a billiard ball is shot west at 2.80 m/s. A second, identical billiard ball is shot east at 1.50 m/s. the balls has a glancing collision, not a head-on-collision, deflecting the second ball by 90 degrees and sending it south at 1.55 m/s. what is the speed of the first ball after the collision? a billiard ball is shot west at 2.80 m/s. A second, identical billiard ball is shot east at 1.50 m/s. the balls has a glancing collision, not a head-on-collision, deflecting the second ball by 90 degrees and sending it south at 1.55 m/s. what is the speed of the first ball after the collision? a billiard ball is shot west at 2.80 m/s. A second, identical billiard ball is shot east at 1.50 m/s. the balls has a glancing collision, not a head-on-collision, deflecting the second ball by 90 degrees and sending it south at 1.55 m/s. what is the speed of the first ball after the collision?

Explanation / Answer

let the horizontal velocity of the first ball be x and the vertical velocity be y.

conserving momentum in the vertical direction,

m*1.55 = m*y

or y=1.55 m/s (north)

conserving momentum in the horizontal direction,

m*2.8 - m*1.5 = m*x

or x=1.3 m/s(west)

so speed of the first ball = (1.3^2 + 1.55^2)^0.5

=2.02 m/s

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