a bicycle rider ( mass of bike and rider is 85kg ) travelling eastat 23ms^-1 cha

Question

a bicycle rider ( mass of bike and rider is 85kg ) travelling eastat 23ms^-1 changes its velocity to 23ms^-1 south in 5 seconds . 1) calculate the acceleration . 2) calculate the change in momentum 3)calculate the impulse given to the bike and rider
south in 5 seconds . 1) calculate the acceleration . 2) calculate the change in momentum 3)calculate the impulse given to the bike and rider

Explanation / Answer

Given , Mass of bike and rider , m = 85 kg Initial Velocity , u = 23im/s         ["i" representthe east direction] Final Velocity , v = 23(-j) m/s = -23j m/s             ["j" represent the north direction , so "-j" represent Southdirection] time , t = 5 sec (i) Accleration Using First equation of motion v = u + at => -23j = 23i + 5a => 5a = -23i - 23j => a = -23(i + j) / 5   m/s2 (ii)Change in momentum p = m(v - u) = 85(-23j - 23i) = (-1955i - 1955j)kg.m/s (iii)Impulse Impulse = change in momentum = p = (-1955i - 1955j) kg.m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.