10\' N Determine the magnetic force on an identical particle when it travels thr

Question

10' N Determine the magnetic force on an identical particle when it travels through the same A charged particle moving through a magnetic field at right angles to the field with a speed of 26.7 m s experiences a magnetic force of 2.98 magnetic field with a speed ot 5.04 mfs at an angle of 32.2° relative to the magnetic field. 2.88e-5 X How does the magnetic force acting on a charged particle moving through a magnetic field depend on the cherge of the particle, speed of the particle, magnitude of the magnetic field, and the direction the perticle is treveling through the magnetic field? For this problem, why have we not been given values for the charge on the particles and the magnetic field? NTutorial

Explanation / Answer

given that

v = 26.7 m/s

F = 2.98*10^-4 N

when particle is perpendicular magnetic field

F = q*v*B

2.98*10^-4 = q*26.7*B

q*B = (2.98*10^-4)/(26.7) = 1.12*10^-5

when particle is makeing an angle 32.2 deg

F = q*v*B*sin(theta)

F = 1.12*10^-5*5.04*sin(32.2)

F = 3*10^-5 N

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