A 2100 kg car traveling to the right at 24 m/s is chasing a second car of the sa

Question

A 2100 kg car traveling to the right at 24 m/s is chasing a second car of the same mass that is traveling to the right at 10 m/s. (a) If the two cars collide and stick together, what is their speed just after the collision? 17 (b) What fraction of the initial kinetic energy of the cars is lost during this collision? -0.14 Where does it go? It is transformed into heat, sound, and the deformation of the metal. It is transmitted to the road. It is converted to momentum. It is returned to the Universe. No kinetic energy is lost.

Explanation / Answer

Initial kinetic energy of the system

K.Ei= 1/2*2100(24^2+10^2)=709800 joule

Final kinetic enrgy of system

K.Ef= 1/2*4200*17^2=606900

Calculate the fraction

Fraction= (709800-606900)/709800=0.144

Hence fraction will be 0.144 with positive sign

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.