(3%) Problem 5: An electron in a TV CRT moves with a speed of 5.5 x 107 m/s, in

Question

(3%) Problem 5: An electron in a TV CRT moves with a speed of 5.5 x 107 m/s, in a direction perpendicular to the Earth's magnetic field, which has a strength of 4.25 x 10 T 50% Part (a) What electric field strength in kV/m must be applied perpendicular to the Earth's magnetic field to make the electron moves in a straight line? Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: Z tan() ( cosO cotan0 asin) acos0 sin % per attempt) detailed view sinh0 atan)acotan() coshO tanhO cotanh0 0 Degrees Radians Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback Submission History Answer Hints Totals 0% Feedback Totals 0% 0% 0% 50% Part (b) If this is done between plates separated by 0.95 cm, what is the voltage applied in V? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a correction.)

Explanation / Answer

here,

speed v = 5.5 * 10^7 m/s

magnetic feild , B = 4.25 * 10^-5 T

a)

let the electric feild strength be E

equating the forces

magnetic force = electric force

q * v * B = q * E

5.5 * 10^7 * 4.25 * 10^-5 = E

E = 2.3 * 10^3 V/m

the electric feild strength is 2.3 KV/m

b)

d = 0.95 cm = 0.0095 m

the voltage applied , V = E * d

V = 0.0095 * 2300 V

V = 21.85 V

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