An electron moving at 3.88x10^3 m/s in 1.23T magnetic field experiences a magnet

Question

An electron moving at 3.88x10^3 m/s in 1.23T magnetic field experiences a magnetic force of 1.40x10^-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0 and 180. Smaller value: Larger value : An electron moving at 3.88x10^3 m/s in 1.23T magnetic field experiences a magnetic force of 1.40x10^-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0 and 180. Smaller value: Larger value : Smaller value: Larger value :

Explanation / Answer

magnetic force acting on an electron

f = qvBsin(theta)

sin(theta) = -1.4*10^-16/1.6*10^-19*3.88*10^3*1.23 = 10.5 or 169.5 degrees

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