EXERCISE HINTS: GETTING STARTED I I\'M STUCK! A circuit consists of a battery wi
ID: 1583487 • Letter: E
Question
EXERCISE HINTS: GETTING STARTED I I'M STUCK! A circuit consists of a battery with a closed circuit, a terminal voltage of 12.0 V, and 1.9-92, 3.0-2, 6.5-2, and 7.5-2 resistors connected in series, oriented as in figure a above, with the battery in the bottom of the loop, positive terminal on the left, and resistors in increasing order, left to right, in the top of the loop (a) Calculate the equivalent resistance of the circuit 18.9 (b) Calculate the current. 635 (c) Calculate the total power dissipated by the load resistors 7.62 (d) What is the electric potential at a point between the 3.0-2 and 6.5-2 resistors, if the electric potential at the positive terminal is 12.0 V? 15.16 Your response differs from the correct answer by more than 10%. Double check your calculations (e) If the battery has an emf of 12.1 V, find the battery's internal resistance 11.465 Your response differs significantly from the correct answer. Rework your solution from thee beginning and check each step carefully. Need Help? ReadIt Submit Answer Save Progress Practice Another VersionExplanation / Answer
d)
here,
current through each resisor is same,
now use,
potential difference,
V=E-I*(R2+R3)
V=12-0.635*(3+6.5)
V=5.97 volts
e)
use,
v=emf-I*r
12=12.1-0.635*r
==> r=0.157 ohms
internal resistance, r=0.157 ohms
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.