Chapter 21 Begin Date: 3/1/2018 12:01:00 AM - Due Date: 3/10/2018 11:59:00 PM En
ID: 1584038 • Letter: C
Question
Chapter 21 Begin Date: 3/1/2018 12:01:00 AM - Due Date: 3/10/2018 11:59:00 PM End Date: 3/10'2018 11:59:00 PM (8%) Problem 10: Consider the following circuit of three resistors (R1·R2, and R3), with batteries that have emfs ei- 19 V and &2-46 V, and internal resistances ri and 12 0.5 Randomized Variables 81 19V 2.5 = 46V 6.0 1.5 0.5 ©theexpertta.com > 33% Part (a) Find the current 11-in amps Grade Summai Deductions Potential 0% 100% Submissions Attempts remaining: S (0% per attempt) detailed view cosO tan() | |( sin cotanasinO atanacotan sinh) cosh) acos tanh)cotanhO) 0 END Degrees Radians Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 4 Feedback: 0% deduction per feedback. 33% Part (b) Find the current /2, in amps 33% Part (c) Find the current 13 in ampsExplanation / Answer
Here ,
Using KCL at the node
I1 - I2 - I3 = 0
Using KVL
19 - 3 * I2 - 6 I1 = 0
46 - 2 * I3 - 6 I1 = 0
solving the equations
I1 = 4.9 A
part B)
I2 = -3.44 A
part C)
I3 = 8.33 A
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