Air at sea level with a temperature of 28° C is forced up a mountain slope and t

Question

Air at sea level with a temperature of 28° C is forced up a mountain slope and the air's dew point temperature is 20° C. If the wet adiabatic lapse rate is 6° C/km, what is the temperature of the air once it is lifted to the top of this 4 km mountain?
Air at sea level with a temperature of 28° C is forced up a mountain slope and the air's dew point temperature is 20° C. If the wet adiabatic lapse rate is 6° C/km, what is the temperature of the air once it is lifted to the top of this 4 km mountain?
Air at sea level with a temperature of 28° C is forced up a mountain slope and the air's dew point temperature is 20° C. If the wet adiabatic lapse rate is 6° C/km, what is the temperature of the air once it is lifted to the top of this 4 km mountain?

Explanation / Answer

Wet adiabetic lapse rate is the rate at which temp of wet air decrease with per km increase of altitude which is in given question= 6o C/km

So at 4km altitute temp. decrease will be =4*6= 24o C

So temp. of the air will be =(28-24)o C=4o C

ANd as the dew poin 20o C at this temp the water vapour in air will condense.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.