Th he ircit shown in the figure below is used to make a magnetic balance to weig

Question

Th he ircit shown in the figure below is used to make a magnetic balance to weigh objects. The mass m to be measured is hung frem the center of the bar, that is in the uniform magnetic field of 1.67 t directed into the plane of the figure. The the battery by thin vertical wires that can bar; the resistance of the rest of the dircuat is much less than this. battery v tage can be adjusted to vary the curent in the d at The horin tal bars 62en lo g ad s made of extr ely igit. idt ma ial it is ected to support no apprecdiable tensionç all the weight of the suspended mass m is supported by the magneic force on the bar. A resistor with R - 5.00 0 is in series with the t Bar × × (a) which point, a or b, should be the positive terminal of the battery? (b) Iif the masimum terminal volitage of the battery is 175 V. what is the grestest mass m that this Instrument can meas kg

Explanation / Answer

given

B = 1.67 T
L = 62.4 cm = 0.624 m
R = 5 ohms

V = 175 V
a) a

when a is positive terminal of the battery current flows in the rod towards right and magnetic force acts upward which balances the weisght of hanging mass.

b) I = V/R

= 175/5

= 35 A

now use

Fg = FB

m*g = B*I*L*sin(90)

m = B*I*L/g

= 1.67*35*0.624/9.8

= 3.72 kg <<<<<<<------------------Answer

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.