Table 5: Static Frictional Force Average apllied force (N) /Normal Force(N) >2.4

Question

Table 5: Static Frictional Force
Average apllied force (N) /Normal Force(N)
>2.47 / >2.31
>3.73 / >3.41
>4.53 / >4.11

Table 6: Kinetic Frictional Force
Average Applied Force (N)/ Normal Force(N)
>1.87 / >1.43
>2.67/ >2.12
>3.6/ >3.71

Please Use the first question to answer the second. I am having difficulty with this therefore I appreciate all the help! Thank you

3. A person applied a horizontal force to a crate of mass, m, that caused the crate to move at a constant velocity (Figure 6). Show that the relationship between the applied force and the normal force is FA- Click here to enter text. Figure 6: A horizontal force Is applied to a crate.

Explanation / Answer

Solving first question

Since it is given that object is moving with constant velocity .It means force applied is equal to friction force to make net force equal to zero

So Fa=fs

And we know

fs=u*Normal force=uFn

Where u is coefficient of friction

So Fa=uFn

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