Capacitors C1 = 10F and C-20F are each charged to 18 V, then disconnected from t

Question

Capacitors C1 = 10F and C-20F are each charged to 18 V, then disconnected from the battery without changing the charge on the capacitor plates. The two capacitors are then connected in parallel, with the positive plate of C connected to the negative plate of C2 and vice versa. Part A Afterward, what is the charge on each capacitor? Express your answer using two significant figures. Enter your answers numerically separated by a comma. 01 02 HAC Submit Incorrect. Try Again: 7 attempts remaining Part B What is the potential difference across each capacitor? Express your answer using two significant figures. Enter your answers numerically separated by a comma. Submit Reguest Answer

Explanation / Answer

charges on capacitors

charge on first capacitor Q1 = C1*V

charge on second capacitor Q2 = C2*V

net charge stored Q = Q2 - Q1

Q = (C2 - C1)*V = (20 - 10)*10^-6*18

Q = 180*10^-6 C

equivalent capacitance Ceq = C1 + C2 = 30 uF

potential across capacitors V' = Q/Ceq = 180/30 = 6 V

charge on capacitor 1 , Q1' = C1*V' = 10*6 = 60 uC

charge on capacitor 2 , Q2' = C2*V' = 20*6 = 120 uC

==================================

dV1 , dV2 = 6 , 6 V

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.