A catapult on a cliff launches a large round rock towards a ship on the ocean be

Question

A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H of 34.0 m above sea level, directed at an angle above the horizontal with an unknown speed v0.

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Explanation / Answer

a)

Horizontal distance travelled is

X=Voxt

171 =Vox*6

Vox=28.5 m/s

From

Y=Yo+Voyt-(1/2)gt2

when it hits ground Y=0

0=34+Voy*6-(1/2)*9.81*62

Voy=23.76 m/s

Initial Direction

o=tan-1(23.76/28.5)=39.82o

b)

Vo=sqrt(28.52+23.762)=37.1 m/s

c)

From

Vfy2=Voy2-2g(Y-Yo)

at Maximum height Vfy=0

=>0=23.762-2*9.81*(H-34)

H=62.78 m=62.8 m

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