A constant potential difference of 17 V is maintained between the terminals of a
ID: 1586460 • Letter: A
Question
A constant potential difference of 17 V is maintained between the terminals of a 0.24-Fparallel-plate air capacitor.
Part A
A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor? (Dielectric constant K of Mylar is 3.1 )
Express your answer using two significant figures.
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Part B
What is the total induced charge on either face of the Mylar sheet?
Express your answer using two significant figures.
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Part C
What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
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A constant potential difference of 17 V is maintained between the terminals of a 0.24-Fparallel-plate air capacitor.
Part A
A sheet of Mylar is inserted between the plates of the capacitor, completely filling the space between the plates. When this is done, how much additional charge flows onto the positive plate of the capacitor? (Dielectric constant K of Mylar is 3.1 )
Express your answer using two significant figures.
Q= CSubmitMy AnswersGive Up
Part B
What is the total induced charge on either face of the Mylar sheet?
Express your answer using two significant figures.
|Qi|= CSubmitMy AnswersGive Up
Part C
What effect does the Mylar sheet have on the electric field between the plates? Explain how you can reconcile this with the increase in charge on the plates, which acts to increase the electric field.
Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
3800 Character(s) remaining
Explanation / Answer
Here ,
potential difference , Vd = 17 V
capacitance , C = 0.24 uF
part A)
k = 3.1
additional charge flowed = (k -1)*C * V
additional charge flowed = (3.1 -1) * 17 * 0.24
additional charge flowed = 8.57 uC
part B)
the total charge induced on either side = additional charge flowed
the total charge induced on either side = 8.57 uC
part C)
when a dielectric is inserted , the electric field will decrease
as the permitivity in dielectric is less than in dielecric.
but as the charge increase , both changes cancel out each others effect.
hence , the electric field remain constant.
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