Two trains, a freight train and a commuter train, are traveling in the same dire

Question

Two trains, a freight train and a commuter train, are traveling in the same direction on parallel tracks. At t = 0 s, the front of the commuter train is some distance ahead of the front of the freight train. Be consistent, and measure everything from the front of each train. The graph above shows the velocities of the two trains from t = 0 s to t = 60 s. Note that both trains have a constant acceleration until t1 = 20.0 s, and then they both travel at constant velocity. Take v = 6.00 m/s. (a) Although the freight train starts behind the commuter train, it eventually catches up. Specifically, there is one instant when the two trains are exactly side-by-side. However, after this instant, the commuter train gets ahead again - the freight train is never ahead.  What is the distance between the two trains at t = 0 s? At the end of the 60-second period, how far is the commuter train ahead of the freight train?

Explanation / Answer

(a) The distance between the two trains at t = 0 sec which is given as :

d = v1 t + v2 t

both trains travel at constant velocity.

d = (6 m/s) (20 s) + (6 m/s) + (20 s)

d = 240 m

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